Answer:
The y-intercept is (0,-12).
Step-by-step explanation:
Given equation is [tex]y=x^2-x-12[/tex].
Now question says to find the y-intercept of the given parabola [tex]y=x^2-x-12[/tex].
We know that y-intercept means the y-value when x-value equals 0
so let's plug x=0 into given equation [tex]y=x^2-x-12[/tex] then solve that for y.
[tex]y=x^2-x-12[/tex]
[tex]y=0^2-0-12[/tex]
[tex]y=0-0-12[/tex]
[tex]y=-12[/tex]
Hence the y-intercept is (0,-12).
