Answer:
[tex]\frac{3x}{5(x+2)}[/tex]
Step-by-step explanation:
Multiply the fractions by multiplying the numerators.
[tex]\frac{6x^2}{x(x-3)} * \frac{(x-3)}{10(x+2)} \\\\\frac{6x^2(x-3)}{10x(x-3)(x+2)} \\\\ \frac{6x}{10(x+2)} \\\\\frac{3x}{5(x+2)}[/tex]
