Answer:
[tex]\large\boxed{-\dfrac{1}{3}(6x+15)-3=-2x-8}[/tex]
Step-by-step explanation:
[tex]-\dfrac{1}{3}(6x+15)-3\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=\left(-\dfrac{1}{3}\right)(6x)+\left(-\dfrac{1}{3}\right)(15)-3\\\\=-2x-5-3\\\\=-2x-8[/tex]
