repirce19 repirce19
  • 24-01-2019
  • Mathematics
contestada

I tried, but can't get any further


Factor:

256z^2 - 4 - 192z^2 + 3

my answer so far:

64z^2 - 1

Respuesta :

LammettHash
LammettHash LammettHash
  • 24-01-2019

The next step would be to recognize your expression as a difference of squares:

[tex]64z^2-1=(8z)^2-1^2[/tex]

We have a neat rule for factorization of a difference of squares:

[tex]a^2-b^2=(a-b)(a+b)[/tex]

So you would have

[tex]64z^2-1=(8z-1)(8z+1)[/tex]

Answer Link

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