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suppose a parabola has an axis of symmetry at x = -5, a maximum height of 9, and passes through the point (-7,1). write an equation of the parabola in vertex from.

Y = -4(x-5)^2+9
Y = -7(x+9)^2 - 5
Y = -0.06(x-5)^2 + 9
Y = -2(x+5)^2 + 9

Help please...

Respuesta :

We are given

a parabola has an axis of symmetry at x = -5, a maximum height of 9

so, we get

vertex =(-5,9)

vertex=(h,k)=(-5,9)

so, h=-5 and k=9

we can use vertex form of parabola

[tex]y=a(x-h)^2+k[/tex]

we can plug these value

[tex]y=a(x+5)^2+9[/tex]

now, it passes through the point (-7,1)

we can use it and then we can solve for a

[tex]1=a(-7+5)^2+9[/tex]

[tex]4a+9=1[/tex]

[tex]4a=-8[/tex]

[tex]a=-2[/tex]

So, we will get equation of parabola as

[tex]y=-2(x+5)^2+9[/tex]..............Answer


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