manyppl9191 manyppl9191
  • 23-10-2018
  • Mathematics
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The equation of a hyperbola is x^2-4y^2-2x-15=0. What is the width of the asymptote rectangle?

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tramserran
tramserran tramserran
  • 23-10-2018

Answer:  8

Step-by-step explanation:

x² - 2x  + ___ - 4y²  = 15 + ___

x² - 2x  + 1 - 4y²  = 15 + 1

(x - 1)² - 4(y)² = 16

[tex]\frac{(x-1)^{2}} {16} - \frac{4(y - 0)^{2}}{16} = \frac{16}{16}[/tex]

[tex]\frac{(x-1)^{2}} {16} - \frac{(y - 0)^{2}}{4} = 1[/tex]

[tex]r_{x} = 4[/tex]   [tex]r_{y} = 2[/tex]

width of rectangle is 2[tex](r_{x})[/tex] = 2(4) = 8

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