oshaquinn oshaquinn

23-10-2018
Mathematics

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Find two consecutive odd integers such that three times the larger is 5 less than four times the smaller

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anonymous12345678901 anonymous12345678901

23-10-2018

Let n=smallest number
Let n+2=largest number

3(n+2)=4(n)-5
3n+6=4n-5
-n=-11
n=11

11+2=13

The smallest number is 11 and the largest number is 13

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