Respuesta :

konrad509

[tex]y=x^2-10x+9\\\\y=x^2-10x+25-16\\\\y=(x-5)^2-16[/tex]

gmany

We must use

[tex](a-b)^2=a^2-2ab+b^2\qquad(*)[/tex]

We have:

[tex]y=x^2-10x+9=x^2-2(x)(5)+9=\underbrace{x^2-2(x)(5)+5^2}_{(*)}-5^2+9\\\\=(x-5)^2-25+9=\boxed{(x-5)^2-16}[/tex]


[tex]a=1,\ h=5,\ k=-16[/tex]

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