heyarbae heyarbae

22-09-2018
Mathematics

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can someone help me work this problem?[tex]\sqrt{2} +8=x+4[/tex]

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Kamikazeminem Kamikazeminem

22-09-2018

[tex] \sqrt{2x} + 8 = x + 4 \\ \sqrt{2x} =x - 4 \\ 2x = {x}^{2} - 8x + 16 \\ {x}^{2} - 10x + 16 = 0 \\ - (x - 2)(x - 8) = 0 \\ x = 8[/tex]

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