n, n + 2, n + 4 - three consecutive odd integers
366 - the sum
Equation:
n + (n + 2) + (n + 4) = 366
n + n + 2 + n + 4 = 366
3n + 6 = 366 |subtract 6 from both sides
3n = 360 |divide both sides by 3
n = 120
n + 2 = 120 + 2 = 122
n + 4 = 120 + 4 = 124
Answer: 120, 122, 124.
