sanpal7649 sanpal7649
  • 21-08-2018
  • Mathematics
contestada

How many positive integers $n$ satisfy $ floor sqrt n floor = 5$?

Respuesta :

DeanR
DeanR DeanR
  • 21-08-2018

That's all the square roots of the form 5.xxxx. The numbers start at 5² and end at 6²-1.

So that's 6² - 5² = 11 numbers. We can list them:

25,26,27,28,29,30,31,32,33,34,35

Answer: 11


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