Respuesta :

FeF₂(s) ⇄ Fe²⁺ + 2 F⁻

let x = [FeF₂]. then [Fe²⁺] = x and [F⁻] = 2x (by the reaction)

Ksp = [Fe²⁺][F⁻]²
2.36 x 10⁻⁶ = x(2x)²
x = 8.387 × 10⁻³ M = [FeF₂]

the solubility of FeF₂ in water is 8.39 × 10⁻³ M
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Answer:

The person above is correct

Explanation:

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