Respuesta :

carlosego
For this case we can make the following rule of three:
 1 box -------------> 15 paperweights
 x -------------------> 1269 paperweights
 We clear the value of x.
 We have then:
 x = (1269/15) * (1)
 x = 84.6
 Rounding to the nearest whole:
 x = 85
 Answer:
 There will be needed about:
 x = 85 boxes
kenide992

[tex]1 - - - - - - - >- 15 \\ x - - - - - - - - 1269 \\ x = 1269 \times 1 \div 15 \\ x = 85boxes[/tex]
hope this help

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