We can convert the logarithmic equation to exponential equation to find its equivalent equation.
[tex]y= log_{ \frac{1}{2} }(x) \\ \\
[/tex]
Shifting the base of log(1/2) to the other side of the equation, we can write:
[tex] (\frac{1}{2})^{y} =x \\ \\
x= \frac{ 1^{y} }{ 2^{y} } \\ \\
x= \frac{1}{ 2^{y} } \\ \\
x= 2^{-y} [/tex]
