Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-2}{ h},\stackrel{5}{ k})\qquad \qquad radius=\stackrel{4}{ r} \\\\\\\ [x-(-2)]^2+[y-5]^2=4^2\implies (x+2)^2+(y-5)^2=16[/tex]

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