[tex]\bf (y-10)^2=2(x-2)\implies y^2-20y+100=2x-4
\\\\\\
\cfrac{y^2-20y+100+4}{2}=x\implies \cfrac{1}{2}y^2-10y+52=x
\\\\\\
\boxed{y-10=\cfrac{dx}{dy}}\qquad
(\stackrel{x}{52.00}~,~\stackrel{y}{0.00})\implies 0-10=\cfrac{dx}{dy}\implies -10=\cfrac{dx}{dy}\\\\
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\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-0=-10(x-52)
\\\\\\
y=-10x+520[/tex]
