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How much heat is released when a 10.0-g sample of iron cools from 75.0°c to 25.5 °c? the specific heat capacity of iron is 0.449 j/g · °c?

Respuesta :

m = 10.0 g, the mass of the iron sample
ΔT = 75 - 25.2 = 49.5°C, the decrease in temperature
c = 0.449 J/(g-°C), the specific heat of iron

The heat released is
Q = m*c*ΔT
    = (10.0 g)*(0.449 J/(g-°C))*(49.5 C)
    = 222.255 J

Answer: 222.3 J (nearest tenth)

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