[tex]\bf 12^{2x-8}=15\\\\
-----------------------------\\\\
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\impliedby thus\\\\
-----------------------------\\\\
log\left( 12^{2x-8} \right)=log(15)\implies (2x-8)log(12)=log(15)
\\\\\\
2x-8=\cfrac{log(15)}{log(12)}\implies 2x=\cfrac{log(15)}{log(12)}+8\implies
x=\cfrac{\frac{log(15)}{log(12)}+8}{2}[/tex]
