We have to calculate the equation of the line. It would be
[tex]m=\frac{3-1}{-2-(-2)}=\frac{1}{2}[/tex]
Since it is needed to obtain a point on the perpendicular line, we must calculate the slope of the perpendicular line
[tex]m1\cdot m2\text{ = -1 so m2=-2}[/tex]
Then as we know the intercept on y is 2 we know b in the equation y=mx+b
After this, we have the equation y=-2x+2
The point that suits for that equation is A (1,0)
