ginazarza
ginazarza
23-10-2016
Chemistry
contestada
as a step O3 0.020 mol to gr
Respuesta :
Willchemistry
Willchemistry
23-10-2016
Molar mass:
Atomic mass O = 16.0 a.m.u
O₃ = 16.0 x 3 => 48.0 g/mol
Therefore:
1 mole O₃ --------------- 48.0 g
0.020 mole O₃ ---------- ??
0.020 x 48.0 / 1 =
0.96 / 1 =>
0.96 g
hope this helps!
Answer Link
VER TODAS LAS RESPUESTAS ( 27+ )
Otras preguntas
Part A What is the main idea of the essay? Support your answer with evidence from the text.Part BWho is the audience for the article? Include details such as ag
SOMEONE HELP ME ON THIS!!
yesterday (was /were) a busy day for us
how did Alexander dye ?
How is suspense created for the reader in this passage.
The function f(x) is shown graphed below. The function g(x) is defined by the formula: g(x)=-4f(x)+7 What is the value of g(3)?
how is unity strength and a binding force?
(mc)for which of the following strategic reasons did the united states acquire the midway islands? to spread christian and democratic ideals to the citizens liv
in a dilation, what is preserved and what is altered?
A strong topic sentence contains a topic which can be supported by Abd M
