micky12330 micky12330
  • 23-08-2020
  • Mathematics
contestada

if
[tex]p(x) = 3x {}^{2} - 2x + 5[/tex]
then find p(-½)

​

Respuesta :

Stephen46
Stephen46 Stephen46
  • 23-08-2020

Answer:

[tex]p( - \frac{1}{2} ) = \frac{27}{4} [/tex]

Step-by-step explanation:

p(x) = 3x² - 2x - 5

To find p( -½) substitute the value of x that's -½ into p(x) and evaluate the value

That's

[tex]p( - \frac{1}{2} ) = 3 ({ - \frac{1}{2} })^{2} - 2( - \frac{1}{2} ) + 5 \\ = 3( \frac{1}{4} ) + 1 + 5 \\ = \frac{3}{4} + 6[/tex]

Find the LCM

The LCM is 4

So we have

[tex]p( - \frac{1}{2} ) = \frac{3}{4} + 6 \\ = \frac{3 + 24}{4} [/tex]

We have the final answer as

[tex]p( - \frac{1}{2} ) = \frac{27}{4} [/tex]

Hope this helps you

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